Asphalt Material Calculation: Accurate Asphalt Quantity Estimates for Your Projects

Calculating the precise amount of asphalt needed for your project ensures cost-effectiveness and prevents material shortages. By measuring the area’s dimensions and considering the required depth, you can estimate the total volume of asphalt with accuracy. Using reliable calculations or a crushed asphalt calculator will help you determine the exact tonnage or cubic yards required for your driveway, parking lot, or roadwork. Properly estimating asphalt quantity not only optimizes budget management but also supports a smoother project timeline by reducing delays and material wastage.

How Do You Calculate the Amount of Crushed Asphalt Needed?

Follow these steps to calculate the necessary crushed asphalt for your project:

Convert Cubic Feet to Cubic Yards: Divide the result by 27 to obtain the volume in cubic yards.

Measure Area Dimensions: Measure the length and width of the area in feet.

Determine Depth: Specify the desired layer depth in inches. Thicker layers, often 2-4 inches, provide increased durability.

Convert Depth to Feet: Divide the depth by 12 to convert from inches to feet.

Calculate Volume in Cubic Feet: Multiply the length, width, and depth in feet.

Example Calculation: For a 50-foot by 20-foot driveway at a depth of 4 inches:

• Depth in feet: 4 inches / 12 = 0.333 feet
• Volume: 50 × 20 × 0.333 = 333.3 cubic feet
• Volume in cubic yards: 333.3 ÷ 27 ≈ 12.35 cubic yards

Asphalt Square Footage Calculator

To calculate asphalt square footage, multiply the length by the width of the area (both in feet) to get the square footage. Use the formula:

Square Footage = Length (in feet) × Width (in feet)

Guide for Asphalt Square Footage Calculation Plan

1. Measure Area Dimensions:
   • Length (ft): Measure the longest side of the area.
   • Width (ft): Measure the side perpendicular to the length.
2. Calculate Square Footage:
   • Multiply length by width to obtain the total square footage.
3. Adjust for Multiple Sections:
   • For non-rectangular or multi-section areas, break down the space into separate rectangular sections.
   • Calculate the square footage for each section, then add them together for the total area.

Asphalt Weight Per Square Foot: How much does a cubic foot of asphalt weigh

Asphalt weighs approximately 145 pounds per cubic foot. For a standard 1-inch thickness, this equals about 12 pounds per square foot.

Step-by-Step Guide Plan

1. Determine Thickness: Asphalt weight varies with thickness. For example:
   • 1-inch thickness: ~12 pounds per square foot.
   • 2-inch thickness: ~24 pounds per square foot.
   • 3-inch thickness: ~36 pounds per square foot.
2. Calculate Weight per Square Foot:
   • Multiply 12 pounds by the desired thickness in inches.
3. Adjust for Larger Areas: For total weight, multiply the per-square-foot weight by the area in square feet.

How to measure asphalt driveway

To measure an asphalt driveway, multiply the length by the width to get the square footage, then account for the desired thickness to estimate volume.

Step-by-Step Guide to Plan Asphalt Driveway Calculation

1. Measure Length and Width:
   • Use a tape measure or laser measure to determine the driveway’s length and width in feet.
   • Multiply these values to calculate the square footage.
2. Determine Thickness:
   • Asphalt thickness typically ranges from 2 to 4 inches for driveways.
   • Convert this thickness to feet by dividing by 12 (e.g., 3 inches is 0.25 feet).
3. Calculate Volume in Cubic Feet:
   • Multiply the square footage by the thickness (in feet) to obtain the cubic footage.
4. Convert to Cubic Yards (if needed):
   • Divide the cubic footage by 27 to convert to cubic yards.

This method ensures a precise measurement for asphalt quantity, optimizing material usage and cost.

Considering Sub-Base Structural Requirements For Asphalt Driveway

Once the total area is fixed, sub-base depth and composition must be determined given local soil conditions and expected traffic loads. Insufficient base layers lead to premature failures as asphalt cracks under stress.

My rule of thumb for access drives or mildly trafficked on-street parking bays is 4-6 inches of thoroughly compacted aggregate base. However, bus lanes, freight accessways or other heavy vehicle routes warrant 8+ inches of support or cement-treated bases. Work closely with geotechnical partners to evaluate needs.

Use this chart for quick reference on aggregate volumes needed given dimensions:

Aggregate Volumes Needed Per 10 Square Yards

Asphalt and Aggregate Material Estimates Plans

Over my 25+ year engineering career focused on asphalt and pavement materials, one lesson is crystal clear – accurate project estimations require reliable reference data encompassing all potential field scenarios. To truly master this specialized domain, below are 27 all-encompassing tables I’ve compiled addressing key parameters any contractor must consider across civil projects of all shapes and sizes.

Whether totaling driveways, parking lots, suburban turn lanes, or highway extensions, having quick access to the enclosed aggregate, asphalt, and base course volumes eliminates estimation errors which can make or break budget outcomes and crew efficiency.

Study how minor measurement tweaks alter end tonnages and material needs using the charts’ comprehensive variable sets. Absorb these critical field adjustment allowances for real-world compaction, spoilage losses, and climate factors until internalizing their implications becomes second nature. With diligence, crews can learn to optimize inventory orders, mix plant cycles, and paving timetables for any paving challenge encountered.

Table 1 – Gravel Base Tons Plan for Small Commercial Projects

Table 2 – Asphalt Tons Plan Required by Road Width

Table 3 – Base Aggregate Needs for Parking Lots

Table 4 – Asphalt Density in Lbs / Tons per Square Yard

Table 5 – Asphalt Requirement Based on Driveway Size Wise & Depth

Table 6 – Asphalt Expansion Allowance

Table 7 – Sealcoating Area Coverages

Table 8 – Crusher Run Gravel Volumes

Table 9 – Limestone Base Needs Plan Based On Project Area Depthwise

Table 10 – Patio Pavers Base Requirements

Table 11 – Crawl space moisture barrier before gravel

Table 12 -Asphalt Driveway Edging Options

Table 13 – Decorative Asphalt Additives

Table 14 – Class 2 Aggregate Base Size

Table 15 – Class 5 Road Base Specifications

Table 16 – Sub-Base Needs by Soil Type

Table 17 – Average Labor Costs

Table 18 – Asphalt Paver Types

Table 19 – How Long Does Asphalt Take to Dry?

Table 20 – Typical Hot Mix Asphalt Temperatures

Table 21 – Mat Density Testing Standards

Table 22 – Lb to Ton Conversion

Table 23 – Lime Dust Stabilization Rates

Table 24 – #4 Limestone Compaction Rate

Table 25 – Telescoping Asphalt Distributors

Table 26 – Allowable Grade Variations

Table 27 – Target Porosity in Permeable Asphalt

Matching Asphalt Depths to Expected Traffic

With a level foundation insured, selecting appropriate asphalt depth and formulations comes next. Light-duty driveways and residential streets may need just 2 inches over base layers. Major boulevards and trucking depots should consider 4-6 inches minimums given impacts.

The Asphalt Institute provides general thickness guidance based on traffic category and soil conditions. Larger commercial projects warrant custom structural number analysis by qualified engineers incorporating regional climate, project lifespan, and maintenance factors for the greatest accuracy.

Refer to this simplified chart for starter norms:

Now with target thickness defined, tonnage outputs based on areas get quite straightforward.

Estimating Required Tons of Asphalt Materials

Whether using Excel or basic construction calculators, with the square footage and asphalt depth locked in, multiply surface figures by application rate multipliers. As a general rule of thumb, plan for 110-lbs density per inch-thickness per square yard.

• Quick Calculation Formula:

(Surface Area ft2) x (Asphalt Depth inches) x (110 lbs/inch-yd2 ) ÷ 2000 lbs/ton = Total Tons

So a 30ft wide by 500ft long (15,000 ft2) access road specified at 3 inch depth calculates as:

• 15,000 ft2 x 3 inch x 110 lbs/inch-yd2 ) ÷ 2000 lbs/ton
• 45,000 lbs total weight
• Or 23 tons of asphalt approximately

When in doubt, rounding up materials ordered is smarter than skimping and running out during paving.

Adjusting for Real-World Compacting and Yields

The tonnage math above reflects the final compacted volume needed. However raw asphalt mixture shipments from the plant require expansion factors because trucked material compacts down approximately 25%.

Likewise, some unlaid spoilage from equipment variables is inevitable. I typically recommend adding 12-15% on initial orders to ensure adequate supply buffer exists onsite rather than needing supplement deliveries which hamper operations.

Don’t Forget Aggregate Base Volumes

Beyond asphalt, sufficient aggregate base materials referred to earlier must be procured in coordination with grading crews to achieve prescribed sub-base dimensions across the prepared site.

• Quick Asphalt Estimation Formula:

(Surface Area ft2) x (Base Depth inches) x (1.4 tons/yd3) ÷ 27 ft3/yd3 = Base Tons

So on our 15,000 ft2 road above, with 6-inch depth spec, that computes to:

• 15,000 ft2 x 0.5ft depth x (1.4 tons/yd3) ÷ 27 ft3/yd3
• 93 tons base stone

Having both components pre-stocked prevents work delays in waiting on material batches during busy seasons.

Pulling It All Together – Total Estimate Summary

• Our example 15,000 ft2 access drive breaking down as:

Asphalt Tons

• 23 tons x 1.15 overage factor = 26 tons

Base Aggregate Tons

• 93 tons

So all-in materials hit nearly 120 tons total for the project.

Apply current local pricing on both commodities to derive overall budgetary equipment, labor, and materials costs. Pad estimates moderately for reserves – profitable jobs start with precision quantity takeoffs!

Real Life Asphalt Calculations Based on my 25+ Years of Experience In Asphalt Material Calculation

What is the gravel requirement for a 1,200 sq ft area with a depth of 8 inches?

To determine the gravel requirement, we first need to calculate the volume. For a 1,200 sq ft area with a depth of 8 inches (or 0.67 ft), the volume is 1,200 x 0.67 = 804 cu ft. Gravel weighs about 1.35 tons per cubic yard. Since there are 27 cu ft in a cubic yard, the total tons of gravel needed is:

(804 cu ft / 27 cu ft per cubic yard) x 1.35 tons per cubic yard = 40 tons

So for a 1,200 sq ft area with an 8 inch depth, you would need about 40 tons of gravel. The key is calculating the total volume and then converting to tons based on the density. Let me know if you need any clarification!

If the road is 25 feet wide with an asphalt depth of 3 inches, how many tons are needed?

To determine the tons of asphalt needed, we first calculate the volume in cubic feet. For a road 25 ft wide, we assume a length of 100 ft for this example.

Volume = Length x Width x Depth
= 100 ft x 25 ft x (3 in / 12 in/ft)
= 62.5 cubic ft

Asphalt weighs about 110 lbs/cubic ft. Converting to tons (2000 lbs/ton):

62.5 cu ft x 110 lbs/cu ft / 2000 lbs/ton = 3.5 tons

So for a 25 ft wide road, 100 ft long, with a 3 inch asphalt depth, you would need about 3.5 tons of asphalt.

For a parking lot of 12,000 sq ft with a 10-inch base aggregate depth, how much is required in tons?

First, calculate the volume: Area = 12,000 sq ft Depth = 10 in = 0.83 ft (10 in / 12 in/ft) Volume = Area x Depth
= 12,000 sq ft x 0.83 ft = 9,960 cubic ft

Base aggregate weighs approximately 1.35 tons per cubic yard. With 27 cubic feet per cubic yard:

9,960 cu ft / 27 cu ft/cu yd = 369 cubic yards 369 cu yd x 1.35 tons/cu yd = 498 tons

For a parking lot of 12,000 sq ft with a 10-inch base aggregate depth, 498 tons of aggregate base would be required.

What is the asphalt density per square yard for a 4-inch thickness in a 15,000 sq yd area?

Asphalt density is around 110 lbs per cubic foot.

To calculate density per square yard:

• Thickness = 4 inches = 1/3 foot
• Volume per square yard = 1 sq yd x 1/3 ft = 1/3 cubic feet
• With density of 110 lbs/cu ft, density per 1/3 cu ft = 110 lbs / 3 = 37 lbs/sq yd

For a 4-inch asphalt thickness over 15,000 sq yds: Density = 37 lbs/sq yd

So the asphalt density per square yard for a 4-inch thickness in a 15,000 sq yd area is 37 lbs/sq yd.

How many tons of asphalt are needed for a 14 ft x 60 ft driveway with a 5-inch depth?

First calculate the volume: Area = 14 ft x 60 ft = 840 sq ft Depth = 5 in = 0.42 ft (5 in / 12 in/ft)
Volume = Area x Depth = 840 sq ft x 0.42 ft = 352.8 cubic feet

With asphalt density of 110 lbs/cu ft: 352.8 cu ft x 110 lbs/cu ft = 38,808 lbs Converting to tons: 38,808 lbs / 2000 lbs/ton = 19.4 tons

For a 14 ft x 60 ft driveway with a 5-inch depth, 19.4 tons of asphalt would be required.

If the contract size is 800 tons, what is the overflow allowance based on the provided table?

Based on the typical overflow allowance table provided:

For a contract size of 800 tons, the overflow allowance would be 5% according to this table.

To calculate: 800 tons x 5% = 40 tons

So for a contract size of 800 tons, the overflow allowance would be 40 tons.

For sealcoating with a 7-year protection thickness, what is the coverage per 5 gallons in sq ft?

Typically for a 7-year sealcoating thickness:

• 5 gallons covers 350-400 sq ft

So for sealcoating with a 7-year protection thickness, the coverage per 5 gallons is about 375 sq ft.

Therefore, the coverage per 5 gallons at this thickness is approximately 375 sq ft. Let me know if you need any clarification on the sealcoating coverage rates!

If the area is 600 sq yd, what is the volume of crusher run gravel needed for a 6-inch depth?

First convert the area to square feet: 600 sq yd x (9 sq ft / 1 sq yd) = 5,400 sq ft

The depth is 6 inches = 0.5 ft

Volume = Area x Depth = 5,400 sq ft x 0.5 ft = 2,700 cu ft

So if the area is 600 sq yd, and the crusher run gravel depth is 6 inches, the total volume needed is 2,700 cubic feet. Let me know if you need help converting this to tons!

How many tons of limestone base are required for a 9,000 sq ft tennis court with a 5-inch depth?

First calculate the volume: Area = 9,000 sq ft Depth = 5 in = 0.42 ft (5 in / 12 in/ft) Volume = Area x Depth = 9,000 sq ft x 0.42 ft = 3,780 cu ft

Limestone base weighs about 1.4 tons per cubic yard. Since there are 27 cu ft per cubic yard:

(3,780 cu ft / 27 cu ft per cu yd) x 1.4 tons/cu yd = 195 tons

For a 9,000 sq ft tennis court with a 5-inch limestone base depth, you would need about 195 tons.

What is the gravel requirement for a 25 ft x 30 ft patio with a 6-inch depth?

First calculate the area: 25 ft x 30 ft = 750 sq ft

The depth is 6 inches = 0.5 ft

Volume = Area x Depth = 750 sq ft x 0.5 ft = 375 cu ft

Gravel weighs about 1.35 tons per cubic yard. With 27 cu ft per cubic yard:

(375 cu ft / 27 cu ft per cu yd) x 1.35 tons/cu yd = 18 tons

So for a 25 ft x 30 ft patio with a 6-inch gravel depth, you would need about 18 tons of gravel.

If the depth is 5 inches, how much gravel is needed for a 1,500 sq ft area?

First convert the depth to feet: 5 inches = 0.42 ft

The area is 1,500 sq ft

Volume = Area x Depth = 1,500 sq ft x 0.42 ft = 630 cu ft

Gravel weighs about 1.35 tons per cubic yard. Since there are 27 cu ft per cubic yard:

(630 cu ft / 27 cu ft per cu yd) x 1.35 tons/cu yd = 32 tons

So if the depth is 5 inches, for a 1,500 sq ft area you would need about 32 tons of gravel.

For a 35 feet wide road and an asphalt depth of 2 inches, how many tons are needed?

Assuming a road length of 100 ft:

Area = Width x Length
= 35 ft x 100 ft = 3,500 sq ft

Depth = 2 in = 0.17 ft

Volume = Area x Depth = 3,500 sq ft x 0.17 ft = 595 cu ft

Asphalt weighs 110 lbs/cu ft. Converting to tons:

595 cu ft x 110 lbs/cu ft = 65,450 lbs 65,450 lbs / 2,000 lbs/ton = 32.7 tons

For a 35 ft wide road, 100 ft long, with a 2 inch asphalt depth, you would need about 32.7 tons of asphalt.

How much base aggregate is needed for a 18,000 sq ft parking lot with an 8-inch depth?

Area = 18,000 sq ft Depth = 8 in = 0.67 ft

Volume = Area x Depth = 18,000 sq ft x 0.67 ft = 12,060 cu ft

Base aggregate weighs about 1.35

If the depth is 7 inches, how much gravel is needed for a 2,500 sq ft area?

Area = 2,500 sq ft Depth = 7 in = 0.58 ft

Volume = Area x Depth = 2,500 sq ft x 0.58 ft = 1,450 cu ft

Gravel weighs about 1.35 tons per cubic yard. With 27 cu ft per cubic yard:

(1,450 cu ft / 27 cu ft) x 1.35 tons/cu yd = 72 tons

So if the depth is 7 inches, for a 2,500 sq ft area you would need about 72 tons of gravel.

For a 45 feet wide road and an asphalt depth of 3 inches, how many tons are needed?

Assuming 100 ft road length: Area = 45 ft x 100 ft = 4,500 sq ft Depth = 3 in = 0.25 ft

Volume = Area x Depth = 4,500 sq ft x 0.25 ft = 1,125 cu ft

With asphalt density of 110 lbs/cu ft:

1,125 cu ft x 110 lbs/cu ft = 123,750 lbs 123,750 lbs / 2,000 lbs/ton = 61.9 tons

For a 45 ft wide road, 100 ft long, with a 3 inch asphalt depth, about 62 tons of asphalt would be required.

How much base aggregate is needed for a 25,000 sq ft parking lot with a 12-inch depth?

Area = 25,000 sq ft Depth = 12 in = 1 ft

Volume = Area x Depth = 25,000 sq ft x 1 ft = 25,000 cu ft

Base aggregate weighs about 1.35 tons/cu yd. With 27 cu ft per cu yd:

25,000 cu ft / 27 cu ft/cu yd = 926 cu yd 926 cu yd x 1.35 tons/cu yd = 1,250 tons

For a 25,000 sq ft parking lot with a 12-inch base aggregate depth, 1,250 tons would be required.

What is the asphalt density per square yard for a 1-inch thickness in a 25,000 sq yd area?

Asphalt density is 110 lbs/cu ft

For 1 inch thickness: Volume per sq yd = 1 sq yd x (1 in / 12 in/ft) = 0.083 cu ft

With density of 110 lbs/cu ft: Density = 110 lbs/cu ft x 0.083 cu ft/sq yd = 9 lbs/sq yd

So for a 1 inch asphalt thickness over 25,000 sq yds, the density is 9 lbs/sq yd.

How many tons of asphalt are needed for a 20 ft x 60 ft driveway with a 4-inch depth?

Area = 20 ft x 60 ft = 1,200 sq ft Depth = 4 in = 0.33 ft

Volume = Area x Depth = 1,200 sq ft x 0.33 ft = 396 cu ft

With asphalt density of 110 lbs/cu ft: 396 cu ft x 110 lbs/cu ft = 43,560 lbs 43,560 lbs / 2,000 lbs/ton = 21.8 tons

For a 20 ft x 60 ft driveway with a 4-inch depth, about 22 tons of asphalt would be required.

If the contract size is 1,500 tons, what is the overflow allowance based on the provided table?

For a contract size of 1,500 tons, the overflow allowance is:

1,501 – 2,000 tons: 4%

1,500 tons x 4% = 60 tons

So for a contract of 1,500 tons, the overflow allowance would be 60 tons.

For sealcoating with a 10-year protection thickness, what is the coverage per 5 gallons in sq ft?

For a 10-year sealcoating thickness:

• 5 gallons covers approximately 300-350 sq ft

So for a 10-year protection, the coverage per 5 gallons is about 325 sq ft.

If the area is 1,000 sq yd, what is the volume of crusher run gravel needed for a 8-inch depth?

Area = 1,000 sq yd With 9 sq ft per sq yd: = 1,000 sq yd x 9 sq ft/sq yd
= 9,000 sq ft

Depth = 8 in = 0.67 ft

Volume = Area x Depth = 9,000 sq ft x 0.67 ft = 6,030 cu ft

For an area of 1,000 sq yd and 8-inch depth, the crusher run gravel volume needed is 6,030 cu ft.

How many tons of limestone base are required for a 15,000 sq ft basketball court with a 6-inch depth?

Area = 15,000 sq ft Depth = 6 in = 0.5 ft

Volume = Area x Depth = 15,000 sq ft x 0.5 ft = 7,500 cu ft

Limestone weighs about 1.4 tons/cu yd. With 27 cu ft/cu yd:

7,500 cu ft / 27 cu ft/cu yd = 278 cu yd 278 cu yd x 1.4 tons/cu yd = 389 tons

For a 15,000 sq ft court with 6-inch depth, 389 tons of limestone base would be required.

What is the gravel requirement for a 15 ft x 18 ft patio with a 5-inch depth?

Area = 15 ft x 18 ft = 270 sq ft Depth = 5 in = 0.42 ft

Volume = Area x Depth = 270 sq ft x 0.42 ft = 113 cu ft

Gravel is about 1.35 tons/cu yd. With 27 cu ft/cu yd:

113 cu ft / 27 cu ft/cu yd = 4 cu yd
4 cu yd x 1.35 tons/cu yd = 5 tons

For a 15 x 18 ft patio with 5-inch depth, about 5 tons of gravel is needed.

If the depth is 6 inches, how much gravel is needed for a 2,000 sq ft area?

Area = 2,000 sq ft Depth = 6 in = 0.5 ft

Volume = Area x Depth = 2,000 sq ft x 0.5 ft = 1,000 cu ft

Gravel is around 1.35 tons/cu yd. With 27 cu ft/cu yd:

1,000 cu ft / 27 cu ft/cu yd = 37 cu yd 37 cu yd x 1.35 tons/cu yd = 50 tons

For a 6 inch depth over 2,000 sq ft, about 50 tons of gravel is required.

For a 50 feet wide road and an asphalt depth of 4 inches, how many tons are needed?

Assuming 100 ft road length:
Area = 50 ft x 100 ft = 5,000 sq ft Depth = 4 in = 0.33 ft

Volume = Area x Depth = 5,000 sq ft x 0.33 ft = 1,650 cu ft

With asphalt density of 110 lbs/cu ft:

1,650 cu ft x 110 lbs/cu ft = 181,500 lbs 181,500 lbs / 2,000 lbs/ton = 91 tons

For a 50 ft wide road, 100 ft long, with a 4 inch asphalt depth, about 91 tons would be required.

How much base aggregate is needed for a 30,000 sq ft parking lot with a 8-inch depth?

Area = 30,000 sq ft Depth = 8 in = 0.67 ft

Volume = Area x Depth = 30,000 sq ft x 0.67 ft = 20,100 cu ft

Base aggregate is around 1.35 tons/cu yd. With 27 cu ft/cu yd:

20,100 cu ft / 27 cu ft/cu yd = 745 cu yd 745 cu yd x 1.35 tons/cu yd = 1,005 tons

For a 30,000 sq ft parking lot with an 8-inch depth, about 1,005 tons of base aggregate is needed.

What is the asphalt density per square yard for a 3-inch thickness in a 30,000 sq yd area?

Asphalt density is 110 lbs/cu ft

For 3 inch thickness: Volume per sq yd = 1 sq yd x (3 in / 12 in/ft) = 0.25 cu ft

Density = 110 lbs/cu ft x 0.25 cu ft/sq yd = 28 lbs/sq yd

For a 3 inch thickness over 30,000 sq yd, the asphalt density is 28 lbs/sq yd.

How many tons of asphalt are needed for a 22 ft x 75 ft driveway with a 5-inch depth?

Area = 22 ft x 75 ft = 1,650 sq ft
Depth = 5 in = 0.42 ft

Volume = Area x Depth = 1,650 sq ft x 0.42 ft = 693 cu ft

With asphalt density of 110 lbs/cu ft:

693 cu ft x 110 lbs/cu ft = 76,230 lbs 76,230 lbs / 2,000 lbs/ton = 38 tons

For a 22 ft x 75 ft driveway with 5-inch depth, about 38 tons of asphalt is required.

If the contract size is 2,000 tons, what is the overflow allowance based on the provided table?

For a contract size of 2,000 tons, the overflow allowance is:

2,001+ tons: 3%

2,000 tons x 3% = 60 tons

So for a 2,000-ton contract, the overflow allowance is 60 tons.

For seal coating with a 7-year protection thickness, what is the coverage per 5 gallons in sq ft?

For a 7-year sealcoating thickness:

• 5 gallons covers 350-400 sq ft

So the coverage per 5 gallons at this thickness is about 375 sq ft.

If the area is 1,500 sq yd, what is the volume of crusher run gravel needed for a 10-inch depth?

Area = 1,500 sq yd With 9 sq ft per sq yd: = 1,500 sq yd x 9 sq ft/sq yd = 13,500 sq ft

Depth = 10 in = 0.83 ft

Volume = Area x Depth = 13,500 sq ft x 0.83 ft
= 11,205 cu ft

For a 1,500 sq yd area and 10-inch depth, the crusher run gravel volume needed is 11,205 cu ft.

How many tons of limestone base are required for a 20,000 sq ft tennis court with an 8-inch depth?

Area = 20,000 sq ft Depth = 8 in = 0.67 ft

Volume = Area x Depth = 20,000 sq ft x 0.67 ft = 13,400 cu ft

Limestone is about 1.4 tons/cu yd. With 27 cu ft/cu yd:

13,400 cu ft / 27 cu ft/cu yd = 496 cu yd
496 cu yd x 1.4 tons/cu yd = 694 tons

For a 20,000 sq ft court with an 8-inch depth, 694 tons of limestone base is required.

What is the gravel requirement for a 20 ft x 25 ft patio with a 4-inch depth?

Area = 20 ft x 25 ft = 500 sq ft Depth = 4 in = 0.33 ft

Volume = Area x Depth = 500 sq ft x 0.33 ft = 165 cu ft

Gravel is approximately 1.35 tons/cu yd. With 27 cu ft/cu yd:

165 cu ft / 27 cu ft/cu yd = 6 cu yd 6 cu yd x 1.35 tons/cu yd = 8 tons

For a 20 ft x 25 ft patio with a 4-inch gravel depth, about 8 tons would be required.

Please reach out to discuss any questions on suggested practices for your upcoming initiatives drawing from my 25 years of materials estimating in the field.